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Feynman–Kac formula : ウィキペディア英語版
Feynman–Kac formula
The Feynman–Kac formula named after Richard Feynman and Mark Kac, establishes a link between parabolic partial differential equations (PDEs) and stochastic processes. It offers a method of solving certain PDEs by simulating random paths of a stochastic process. Conversely, an important class of expectations of random processes can be computed by deterministic methods. Consider the PDE
:\frac(x,t) + \mu(x,t) \frac(x,t) + \tfrac \sigma^2(x,t) \frac(x,t) -V(x,t) u(x,t) + f(x,t) = 0,
defined for all ''x'' in R and ''t'' in (''T'' ), subject to the terminal condition
:u(x,T)=\psi(x),
where μ, σ, ψ, ''V'', ''f'' are known functions, ''T'' is a parameter and u:\mathbb\times()\to\mathbb is the unknown. Then the Feynman–Kac formula tells us that the solution can be written as a conditional expectation
: u(x,t) = E^Q\left(\int_t^T e^f(X_r,r)dr + e^\psi(X_T) \Bigg| X_t=x \right )
under the probability measure Q such that ''X'' is an Itō process driven by the equation
:dX = \mu(X,t)\,dt + \sigma(X,t)\,dW^Q,
with ''WQ''(''t'') is a Wiener process (also called Brownian motion) under ''Q'', and the initial condition for ''X''(''t'') is ''X''(t) = ''x''.
== Proof ==
Let ''u''(''x'', ''t'') be the solution to above PDE. Applying Itō's lemma to the process
: Y(s) = e^ u(X_s,s)+ \int_t^s e^f(X_r,r) \, dr
one gets
:
\begin
dY = \,du(X_s,s) \\()
& f(X_r,r) \, dr\right)
\end

Since
:d\left(e^\right) =-V(X_s,s) e^ \,ds,
the third term is O(dt \, du) and can be dropped. We also have that
: d\left(\int_t^s e^f(X_r,r)dr\right) = e^ f(X_s,s) ds.
Applying Itō's lemma once again to du(X_s,s), it follows that
:
\begin
dY= +\frac+\tfrac\sigma^2(X_s,s)\frac\right)\,ds \\()
& \,dW.
\end

The first term contains, in parentheses, the above PDE and is therefore zero. What remains is
:dY=e^\sigma(X,s)\frac\,dW.
Integrating this equation from ''t'' to ''T'', one concludes that
: Y(T) - Y(t) = \int_t^T e^\sigma(X,s)\frac\,dW.
Upon taking expectations, conditioned on ''Xt'' = ''x'', and observing that the right side is an Itō integral, which has expectation zero, it follows that
:E(X_t=x ) = E(X_t=x ) = u(x,t).
The desired result is obtained by observing that
:E(X_t=x ) = E \left ()

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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